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vultr: Make get_result handle list (#42890)

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Currently get_result() can only handle a dict. When requiring facts, and
when there is more than one fact, get_result() should be able to handle
a list of dicts, so the normalization process happens to all the items.
This commit is contained in:
Yanis Guenane 2018-07-17 16:24:21 +02:00 committed by René Moser
parent b6e9df2065
commit 577427b1c2
1 changed files with 20 additions and 13 deletions
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33
lib/ansible/module_utils/vultr.py
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@ -225,20 +225,27 @@ class Vultr:
self.module.fail_json(msg="Could not find %s with %s: %s" % (resource, key, value))
def normalize_result(self, resource):
for search_key, config in self.returns.items():
if search_key in resource:
if 'convert_to' in config:
if config['convert_to'] == 'int':
resource[search_key] = int(resource[search_key])
elif config['convert_to'] == 'float':
resource[search_key] = float(resource[search_key])
elif config['convert_to'] == 'bool':
resource[search_key] = True if resource[search_key] == 'yes' else False
if 'key' in config:
resource[config['key']] = resource[search_key]
return resource
def get_result(self, resource):
if resource:
for search_key, config in self.returns.items():
if search_key in resource:
if 'convert_to' in config:
if config['convert_to'] == 'int':
resource[search_key] = int(resource[search_key])
elif config['convert_to'] == 'float':
resource[search_key] = float(resource[search_key])
elif config['convert_to'] == 'bool':
resource[search_key] = True if resource[search_key] == 'yes' else False
if isinstance(resource, list):
self.result[self.namespace] = [self.normalize_result(item) for item in resource]
else:
self.result[self.namespace] = self.normalize_result(resource)
if 'key' in config:
self.result[self.namespace][config['key']] = resource[search_key]
else:
self.result[self.namespace][search_key] = resource[search_key]
return self.result