From e377df2ab0d626830b6695f6fe6bf038783b42b8 Mon Sep 17 00:00:00 2001
From: Hayden <64056131+hay-kot@users.noreply.github.com>
Date: Tue, 15 Mar 2022 12:51:15 -0800
Subject: [PATCH] capture #1043 (#1055)

---
 .flake8                            | 2 +-
 mealie/services/scraper/cleaner.py | 7 ++++++-
 2 files changed, 7 insertions(+), 2 deletions(-)

diff --git a/.flake8 b/.flake8
index c4ae7060..57e78331 100644
--- a/.flake8
+++ b/.flake8
@@ -1,5 +1,5 @@
 [flake8]
-ignore = [
+extend-ignore = [
     E501 # Line Length - See Black Config in pyproject.toml
     E402 # Import Not at Top of File
 ]
diff --git a/mealie/services/scraper/cleaner.py b/mealie/services/scraper/cleaner.py
index 0f65b40c..948d87d1 100644
--- a/mealie/services/scraper/cleaner.py
+++ b/mealie/services/scraper/cleaner.py
@@ -98,7 +98,12 @@ def clean_nutrition(nutrition: Optional[dict]) -> dict[str, str]:
 
     output_nutrition = {key: val.replace(",", ".") for key, val in output_nutrition.items()}
 
-    if "sodiumContent" in nutrition and "m" not in nutrition["sodiumContent"] and "g" in nutrition["sodiumContent"]:
+    if (
+        "sodiumContent" in nutrition
+        and type(nutrition["sodiumContent"]) == str
+        and "m" not in nutrition["sodiumContent"]
+        and "g" in nutrition["sodiumContent"]
+    ):
         # Sodium is in grams. Parse its value, multiple by 1k and return to string.
         try:
             output_nutrition["sodiumContent"] = str(float(output_nutrition["sodiumContent"]) * 1000)